The replacement of $Cl$ in chlorobenzene to form phenol requires drastic conditions,but the chlorine in $2,4-$dinitrochlorobenzene is readily replaced because:

  • A
    $NO_2$ makes the ring electron-rich at the ortho and para positions.
  • B
    $NO_2$ withdraws $e^-$ from the meta position.
  • C
    $NO_2$ donates $e^-$ at the meta position.
  • D
    $NO_2$ withdraws $e^-$ from the ortho and para positions.

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Similar Questions

Arrange the following compounds in decreasing order of their rate of $S_NAr$ reaction:
$(i)$ $p$-nitrochlorobenzene
(ii) $m$-nitrochlorobenzene
(iii) $2,4$-dinitrochlorobenzene
(iv) chlorobenzene
$(v)$ $2,4,6$-trinitrochlorobenzene

Why does the presence of a $-NO_2$ group at the $o,p$-positions increase the reactivity of haloarenes towards nucleophilic substitution reactions?

As compared with chlorocyclohexane, which of the following statements correctly apply to chlorobenzene?
$A$. The magnitude of negative charge is more on chlorine atoms.
$B$. The $C-Cl$ bond has partial double bond character.
$C$. $C-Cl$ bond is less polar.
$D$. $C-Cl$ bond is longer due to repulsion between delocalised electrons of the aromatic ring and lone pairs of electrons of chlorine.
$E$. The $C-Cl$ bond is formed using $sp^2$ hybridised orbital of carbon.
Choose the correct answer from the options given below:

The major product obtained from the reaction of $p-$chlorotoluene with $KNH_2$ in liquid $NH_3$ is ..........

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The decreasing order of reactivity of the given compounds towards nucleophilic substitution with aqueous $NaOH$ is:
$(I)$ $1$-bromo-$3$-nitrobenzene
$(II)$ $1$-bromo-$2,4,6$-trinitrobenzene
$(III)$ $1$-bromo-$4$-nitrobenzene
$(IV)$ $1$-bromo-$2,4$-dinitrobenzene

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